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投稿 #7027 の式を借りました。N88互換BASICで確認。

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1 z=08:n=8:c=1:if n<3 then n=n+12
2 for y=z to 13:for m=n+1 to 15:if 0<(m*26\10+y+y\4)mod 7 then 4
3 ?c,y+2000+m\14;(m-2)mod 12+1;13:c=c+1
4 n=3:next m,y

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